关于 xml:XSLT 显示功绩徽章的问题

XSLT trouble with displaying merit badges

我在尝试显示 1 名侦察员的所有功绩徽章时遇到了麻烦……而且我想不出一个可行的解决方案。例如，我希望它像这样显示(带换行符)：

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First Aid
Swimming
Life saving
…

到目前为止，它只显示每个侦察兵的第一个，即急救

这是 XML：

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<?xml version =“1.0” encoding =“utf-8”?>
<!DOCTYPE bsa SYSTEM“assign08.dtd”>
<?xml-stylesheet type=“text/xsl” href=“assign08.xsl”?>
<bsa>
<council name =“jedi”>
<troop number =“01” unitname=“ok”>
<scout>
<firstname>John</firstname>
<lastname>Smith</lastname>
<phone>111-111-1111</phone>

<street>Fork St.</street>
<city>Portland</city>
<state>OR</state>
</address>
<rank date-earned =“1/1/01”>Eagle</rank>
<meritbadge date-earned =“1/1/00”>First Aid</meritbadge>
<meritbadge date-earned =“2/1/00”>Swimming</meritbadge>
<meritbadge date-earned =“3/1/00”>Life Saving</meritbadge>
<meritbadge date-earned =“4/1/00”>Environmental Science</meritbadge>
<meritbadge date-earned =“5/1/00”>Camping</meritbadge>
<meritbadge date-earned =“6/1/00”>Cooking</meritbadge>
<meritbadge date-earned =“7/1/00”>Safety</meritbadge>
<meritbadge date-earned =“8/1/00”>Basket Weaving</meritbadge>
<meritbadge date-earned =“9/1/00”>Wood carving</meritbadge>
<meritbadge date-earned =“10/1/00”>Archery</meritbadge>
</scout>
<scout>
<firstname>Bill</firstname>
<lastname>Joel</lastname>
<phone>111-111-1112</phone>

<street>Fork St.</street>
<city>Portland</city>
<state>OR</state>
</address>
<rank date-earned =“2/2/02”>Eagle</rank>
<meritbadge date-earned =“1/1/00”>First Aid</meritbadge>
<meritbadge date-earned =“2/1/00”>Swimming</meritbadge>
<meritbadge date-earned =“3/1/00”>Life Saving</meritbadge>
<meritbadge date-earned =“4/1/00”>Environmental Science</meritbadge>
<meritbadge date-earned =“5/1/00”>Camping</meritbadge>
<meritbadge date-earned =“6/1/00”>Cooking</meritbadge>
<meritbadge date-earned =“7/1/00”>Safety</meritbadge>
<meritbadge date-earned =“8/1/00”>Basket Weaving</meritbadge>
<meritbadge date-earned =“9/1/00”>Wood carving</meritbadge>
<meritbadge date-earned =“10/1/00”>Archery</meritbadge>
</scout>

…

这里是 XSL：

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<?xml version=“1.0” encoding=“UTF-8”?>

<xsl:stylesheet version=“1.0”
xmlns:xsl=“http://www.w3.org/1999/XSL/Transform”>

<xsl:template match=“/”>
<html>
<body>
Buy Scouts of America
<table border=“1”>
<tr bgcolor=“#9acd32”>
<th>Last Name</th>
<th>First Name</th>
<th>Phone Number</th>
<th>Address</th>
<th>Rank</th>
<th>Merit Badges</th>
</tr>
<xsl:for-each select=“bsa/council/troop/scout”>
<xsl:sort select=“lastname”/>
<tr>
<td><xsl:value-of select=“lastname”/></td>
<td><xsl:value-of select=“firstname”/></td>
<td><xsl:value-of select=“phone”/></td>
<td><xsl:value-of select=“address”/></td>
<td><xsl:value-of select=“rank”/></td>
<td><xsl:value-of select=“meritbadge”/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>

</xsl:stylesheet>

这是因为您使用的是 XSLT 1.0 和 xsl:value-of。在 1.0 中，xsl:value-of 只会给你第一次出现的值。

尝试使用 <xsl:apply-templates select=”meritbadge”/> 代替。如果您需要更改输出的格式，请添加一个与 meritbadge 匹配的模板，并按您喜欢的格式设置。示例：

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<xsl:template match=“meritbadge”>
<xsl:value-of select=“.”/>
<br/>
</xsl:template>

另外(不相关)你有”购买美国童子军”而不是”美国童子军”。

EDIT – 修改后的 XSLT 的完整示例

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<xsl:stylesheet version=“1.0”
xmlns:xsl=“http://www.w3.org/1999/XSL/Transform”>

<xsl:template match=“/”>
<html>
<body>
Buy Scouts of America
<table border=“1”>
<tr bgcolor=“#9acd32”>
<th>Last Name</th>
<th>First Name</th>
<th>Phone Number</th>
<th>Address</th>
<th>Rank</th>
<th>Merit Badges</th>
</tr>
<xsl:for-each select=“bsa/council/troop/scout”>
<xsl:sort select=“lastname”/>
<tr>
<td><xsl:value-of select=“lastname”/></td>
<td><xsl:value-of select=“firstname”/></td>
<td><xsl:value-of select=“phone”/></td>
<td><xsl:value-of select=“address”/></td>
<td><xsl:value-of select=“rank”/></td>
<td><xsl:apply-templates select=“meritbadge”/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>

<xsl:template match=“meritbadge”>
<xsl:value-of select=“.”/>
<br/>
</xsl:template>

</xsl:stylesheet>

编辑 #2 – 独立的议会/部队

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<xsl:stylesheet version=“1.0” xmlns:xsl=“http://www.w3.org/1999/XSL/Transform”>
<xsl:output indent=“yes”/>
<xsl:strip-space elements=“*”/>

<xsl:template match=“/*”>
<html>
<body>
Boy Scouts of America
<xsl:apply-templates select=“council”/>
</body>
</html>
</xsl:template>

<xsl:template match=“council”>
<xsl:value-of select=“@name”/>
<xsl:apply-templates select=“troop”/>
</xsl:template>

<xsl:template match=“troop”>
<xsl:value-of select=“concat(@number,’ – ‘,@unitname)”/>
<table border=“1”>
<tr bgcolor=“#9acd32”>
<th>Last Name</th>
<th>First Name</th>
<th>Phone Number</th>
<th>Address</th>
<th>Rank</th>
<th>Merit Badges</th>
</tr>
<xsl:apply-templates select=“scout”>
<xsl:sort select=“lastname”/>
</xsl:apply-templates>
</table>
</xsl:template>

<xsl:template match=“scout”>
<tr>
<td><xsl:apply-templates select=“lastname”/></td>
<td><xsl:apply-templates select=“firstname”/></td>
<td><xsl:apply-templates select=“phone”/></td>
<td><xsl:apply-templates select=“address”/></td>
<td><xsl:apply-templates select=“rank”/></td>
<td><xsl:apply-templates select=“meritbadge”/></td>
</tr>
</xsl:template>

<xsl:template match=“meritbadge|address/*”>
<xsl:value-of select=“.”/>
<br/>
</xsl:template>

</xsl:stylesheet>

XSLT trouble with displaying merit badges

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