Converting number into words using if else
我是 c 的初学者。我编写了一个程序来将数字转换为单词。对于 11-19 之间的数字和像这样的数字 20、30、40、50、60、70、80、90,我得到了错误的输出。我还尝试在最后两个 if 语句之间添加 else 语句,这样即使第一个 if 为真,它也不会执行所有 if 语句,但它给了我一个错误,即 “else without a previous if”。
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//This program converts number into words
#include<iostream> using namespace std; main() { int number,unit,ten; cout<<“Please enter any number between 0-99:”; cin>>number; ten=number/10; unit=number%10; if(number<0 | number>99) cout<<“Number is out of range”; if(number>=11 && number <=19); { if(number==11) cout<<“eleven”; if(number==12) cout<<“twelve”; if(number==13) cout<<“thirteen”; if(number==14) cout<<“fourteen”; if(number==15) cout<<“fifteen”; if(number==16) cout<<“sixteen”; if(number==17) cout<<“seventeen”; if(number==18) cout<<“eighteen”; if(number==19) cout<<“ninteen”; } if(ten>=2 && ten<=9) { if(ten==1) cout<<“ten”; if(ten==2) cout<<“twenty”; if(ten==3) cout<<“thirty”; if(ten==4) cout<<“fourty”; if(ten==5) cout<<“fifty”; if(ten==6) cout<<“sixty”; if(ten==7) cout<<“seventy”; if(ten==8) cout<<“eighty”; if(ten==9) cout<<“ninty”; } if(unit>=0 && unit <=9) { if(unit==0) cout<<” zero”; if(unit==1) cout<<” one”; if(unit==2) cout<<” two”; if(unit==3) cout<<” three”; if(unit==4) cout<<” four”; if(unit==5) cout<<” five”; if(unit==6) cout<<” six”; if(unit==7) cout<<” seven”; if(unit==8) cout<<” eight”; if(unit==9) cout<<” nine”; } } |
输出1:-
1
2 |
Please enter any number between 0–99: 12
twelve two |
输出2:-
1
2 |
Please enter any number between 0–99: 30
thirty zero |
- 打开编译器警告。
- 您的代码中还有另一个错误,但您很幸运它没有咬您。当您打算使用逻辑 OR || 时,您使用的是按位 OR |: if (number < 0 || number > 99) 它似乎仍然有效的原因是一些历史原因的巧合。
- 代码风格:在 if 和它的开头 ( 之间总是有一个空格。操作数之间还有一个空格:unit == 7 而不是 unit==7。我知道这听起来无关紧要,但这是你的手艺,就这样对待吧。
在第二个 if 之后有一个分号 ;。此外,您应该使用 || 而不是 |。你也应该排除 ten==1.
时的情况
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//This program converts number into words
#include<iostream> using namespace std; main() { int number,unit,ten; cout<<“Please enter any number between 0-99:”; cin>>number; ten=number/10; unit=number%10; if(number<0 || number>99) { cout<<“Number is out of range”; } if(ten == 1) { if(number==10) cout<<“ten”; if(number==11) cout<<“eleven”; if(number==12) cout<<“twelve”; if(number==13) cout<<“thirteen”; if(number==14) cout<<“fourteen”; if(number==15) cout<<“fifteen”; if(number==16) cout<<“sixteen”; if(number==17) cout<<“seventeen”; if(number==18) cout<<“eighteen”; if(number==19) cout<<“ninteen”; } else { if(ten==2) cout<<“twenty”; if(ten==3) cout<<“thirty”; if(ten==4) cout<<“fourty”; if(ten==5) cout<<“fifty”; if(ten==6) cout<<“sixty”; if(ten==7) cout<<“seventy”; if(ten==8) cout<<“eighty”; if(ten==9) cout<<“ninty”; // **** |
所有情况的输出:
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Please enter any number between 0–99: –1
Number is out of range Please enter any number between 0–99: 0 Please enter any number between 0–99: 1 Please enter any number between 0–99: 2 Please enter any number between 0–99: 3 Please enter any number between 0–99: 4 Please enter any number between 0–99: 5 Please enter any number between 0–99: 6 Please enter any number between 0–99: 7 Please enter any number between 0–99: 8 Please enter any number between 0–99: 9 Please enter any number between 0–99: 10 Please enter any number between 0–99: 11 Please enter any number between 0–99: 12 Please enter any number between 0–99: 13 Please enter any number between 0–99: 14 Please enter any number between 0–99: 15 Please enter any number between 0–99: 16 Please enter any number between 0–99: 17 Please enter any number between 0–99: 18 Please enter any number between 0–99: 19 Please enter any number between 0–99: 20 Please enter any number between 0–99: 21 Please enter any number between 0–99: 22 Please enter any number between 0–99: 23 Please enter any number between 0–99: 24 Please enter any number between 0–99: 25 Please enter any number between 0–99: 26 Please enter any number between 0–99: 27 Please enter any number between 0–99: 28 Please enter any number between 0–99: 29 Please enter any number between 0–99: 30 Please enter any number between 0–99: 31 Please enter any number between 0–99: 32 Please enter any number between 0–99: 33 Please enter any number between 0–99: 34 Please enter any number between 0–99: 35 Please enter any number between 0–99: 36 Please enter any number between 0–99: 37 Please enter any number between 0–99: 38 Please enter any number between 0–99: 39 Please enter any number between 0–99: 40 Please enter any number between 0–99: 41 Please enter any number between 0–99: 42 Please enter any number between 0–99: 43 Please enter any number between 0–99: 44 Please enter any number between 0–99: 45 Please enter any number between 0–99: 46 Please enter any number between 0–99: 47 Please enter any number between 0–99: 48 Please enter any number between 0–99: 49 Please enter any number between 0–99: 50 Please enter any number between 0–99: 51 Please enter any number between 0–99: 52 Please enter any number between 0–99: 53 Please enter any number between 0–99: 54 Please enter any number between 0–99: 55 Please enter any number between 0–99: 56 Please enter any number between 0–99: 57 Please enter any number between 0–99: 58 Please enter any number between 0–99: 59 Please enter any number between 0–99: 60 Please enter any number between 0–99: 61 Please enter any number between 0–99: 62 Please enter any number between 0–99: 63 Please enter any number between 0–99: 64 Please enter any number between 0–99: 65 Please enter any number between 0–99: 66 Please enter any number between 0–99: 67 Please enter any number between 0–99: 68 Please enter any number between 0–99: 69 Please enter any number between 0–99: 70 Please enter any number between 0–99: 71 Please enter any number between 0–99: 72 Please enter any number between 0–99: 73 Please enter any number between 0–99: 74 Please enter any number between 0–99: 75 Please enter any number between 0–99: 76 Please enter any number between 0–99: 77 Please enter any number between 0–99: 78 Please enter any number between 0–99: 79 Please enter any number between 0–99: 80 Please enter any number between 0–99: 81 Please enter any number between 0–99: 82 Please enter any number between 0–99: 83 Please enter any number between 0–99: 84 Please enter any number between 0–99: 85 Please enter any number between 0–99: 86 Please enter any number between 0–99: 87 Please enter any number between 0–99: 88 Please enter any number between 0–99: 89 Please enter any number between 0–99: 90 Please enter any number between 0–99: 91 Please enter any number between 0–99: 92 Please enter any number between 0–99: 93 Please enter any number between 0–99: 94 Please enter any number between 0–99: 95 Please enter any number between 0–99: 96 Please enter any number between 0–99: 97 Please enter any number between 0–99: 98 Please enter any number between 0–99: 99 Please enter any number between 0–99: 100 |
- 接得好!具有讽刺意味的是,第二个 if 完全没有必要,因为它的主体中的 if 语句处理了它的工作。
- 现在它适用于 11 到 19 之间的数字,但它仍然为数字 10、20、30 等提供错误的输出。 30 的输出是”三十零”。
- @MoazAli,感谢您指出。我稍微改变了程序逻辑,现在它适用于所有情况。
以下 code 可以工作:
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//This program converts number into words
#include<iostream> using namespace std; int main() { int number,unit,ten; cout<<“Please enter any number between 0-99:”; cin>>number; ten=number/10; unit=number%10; if(number<0 || number>99) cout<<“Number is out of range”; if(number>=11 && number <=19) { if(number==11) cout<<“eleven”; if(number==12) cout<<“twelve”; if(number==13) cout<<“thirteen”; if(number==14) cout<<“fourteen”; if(number==15) cout<<“fifteen”; if(number==16) cout<<“sixteen”; if(number==17) cout<<“seventeen”; if(number==18) cout<<“eighteen”; if(number==19) cout<<“ninteen”; } else { if(ten>=2 && ten<=9) { if(ten==1) cout<<“ten”; if(ten==2) cout<<“twenty”; if(ten==3) cout<<“thirty”; if(ten==4) cout<<“fourty”; if(ten==5) cout<<“fifty”; if(ten==6) cout<<“sixty”; if(ten==7) cout<<“seventy”; if(ten==8) cout<<“eighty”; if(ten==9) cout<<“ninty”; } if(unit>=0 && unit <=9) { if(unit==0) cout<<” zero”; if(unit==1) cout<<” one”; if(unit==2) cout<<” two”; if(unit==3) cout<<” three”; if(unit==4) cout<<” four”; if(unit==5) cout<<” five”; if(unit==6) cout<<” six”; if(unit==7) cout<<” seven”; if(unit==8) cout<<” eight”; if(unit==9) cout<<” nine”; } } return 0; |
- 我不同意”在 int main() 中添加 return 0;”。当然可以这样做,但是在简洁很重要的stackoverflow问题中,最好让编译器为您添加它;)仍然赞成
对于这种情况,switch 语句更有意义。试试这个代码:
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#include<iostream>
using namespace std; int main() { for (int number = 1; number <= 99; number++) { int ten=number/10; int unit=number%10; if(number<0 || number>99) { cout<<“Number is out of range”; return 1; } if(ten == 1) { switch ( number ) { case 10: cout<<“ten”; break; case 11: cout<<“eleven”; break; case 12: cout<<“twelve”; break; case 13: cout<<“thirteen”; break; case 14: cout<<“fourteen”; break; case 15: cout<<“fifteen”; break; case 16: cout<<“sixteen”; break; case 17: cout<<“seventeen”; break; case 18: cout<<“eighteen”; break; case 19: cout<<“nineteen”; break; } } else { if(ten>=2 && ten<=9) { switch (ten) { case 2: cout<<“twenty”; break; case 3: cout<<“thirty”; break; case 4: cout<<“fourty”; break; case 5: cout<<“fifty”; break; case 6: cout<<“sixty”; break; case 7: cout<<“seventy”; break; case 8: cout<<“eighty”; break; case 9: cout<<“ninty”; break; } } if ( unit != 0 and ten != 0 ) { cout <<“”; } switch ( unit ) { case 0: if ( ten == 0 ) cout<<“zero”; break; case 1: cout<<“one”; break; case 2: cout<<“two”; break; case 3: cout<<“three”; break; case 4: cout<<“four”; break; case 5: cout<<“five”; break; case 6: cout<<“six”; break; case 7: cout<<“seven”; break; case 8: cout<<“eight”; break; case 9: cout<<“nine”; break; } } cout <<“\ “; } return 0; } |
我还发现了以下错误:
由于您的if条件,您得到的实际上是正确的。如果您写下 3 个 if 条件,它将检查其中的三个。另外,去掉第二个 if!
的分号
所以第一个 12 转到第一个 if 并打印 “twelve”。
转到第二个 if。 12/10 是 1.2,所以作为一个 int,它是 `1。它不会进入第二个 if。由于分号,它无论如何都不会进入。
但它进入第三个:12%10。
你的ifs就是这样!
另外,我担心这对你有用:if(number<0 | number>99),因为它应该是 ||,而不是 |。
来源:https://www.codenong.com/53040738/